What are the solutions to the equation 2x+x^2=8 ?

The solutions to the equation 2x+x^2=8 are x=2,x=-4

Find the zeros of 2x+x^2=8

The zeros of 2x+x^2=8 are x=2,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x + x^{2} = 8

x = 2, x = - 4

Solution steps

2 x + x^{2} = 8

Move

8

to the left side

2 x + x^{2} - 8 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

\frac{2}{3} = \frac{1}{2} (- 6 a + 8)

\frac{( 6 m ^{6} n ^{- 2} )}{( 3 m ^{4} n ^{2} ) ^{3}}

3 x + 6 = 2 x + 13

7 n - 5 < 23

3 x^{2} - 5 x - 1 > (x - 3) (x + 3)

What are the solutions to the equation 2x+x^2=8 ?
The solutions to the equation 2x+x^2=8 are x=2,x=-4
Find the zeros of 2x+x^2=8
The zeros of 2x+x^2=8 are x=2,x=-4