What is factor x^5+5x^2-4x^3-20 ?

The solution to factor x^5+5x^2-4x^3-20 is (x+2)(x-2)(x^3+5)

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factor x^5+5x^2-4x^3-20

factor

x^{5} + 5 x^{2} - 4 x^{3} - 20

(x + 2) (x - 2) (x^{3} + 5)

Solution steps

x^{5} + 5 x^{2} - 4 x^{3} - 20

Write in the standard form

= x^{5} - 4 x^{3} + 5 x^{2} - 20

= (x^{5} - 4 x^{3}) + (5 x^{2} - 20)

Factor out

x^{3}

from

x^{5} - 4 x^{3} : x^{3} (x^{2} - 4)

Factor out

5

from

5 x^{2} - 20 : 5 (x^{2} - 4)

= x^{3} (x^{2} - 4) + 5 (x^{2} - 4)

Factor out common term

x^{2} - 4

= (x^{2} - 4) (x^{3} + 5)

Factor

x^{2} - 4 : (x + 2) (x - 2)

= (x + 2) (x - 2) (x^{3} + 5)

2 (0) + y = 4

20 + x + 2 x = 100

2 (6 x + x^{2}) = - 14

\frac{1}{n ^{3}} \cdot \frac{( n + 1 ) ( 2 n + 1 )}{6}

4 x + 6

What is factor x^5+5x^2-4x^3-20 ?
The solution to factor x^5+5x^2-4x^3-20 is (x+2)(x-2)(x^3+5)