What are the solutions to the equation 2x^2-8x+6=0 ?

The solutions to the equation 2x^2-8x+6=0 are x=3,x=1

Find the zeros of 2x^2-8x+6=0

The zeros of 2x^2-8x+6=0 are x=3,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 8 x + 6 = 0

x = 3, x = 1

Solution steps

2 x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4}{2 \cdot 2} : 3

x = \frac{- ( - 8 ) - 4}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

x^{4} - 2 x^{2} - 3

\frac{5}{89}

30 x^{3} + 26 x^{2} + 4 x

x^{2} - 4 x - 21 \geq 0

\frac{9 ^{7}}{9 ^{5}}

What are the solutions to the equation 2x^2-8x+6=0 ?
The solutions to the equation 2x^2-8x+6=0 are x=3,x=1
Find the zeros of 2x^2-8x+6=0
The zeros of 2x^2-8x+6=0 are x=3,x=1