What are the solutions to the equation (3x+6)^2+4(3x+6)+4=0 ?

The solutions to the equation (3x+6)^2+4(3x+6)+4=0 are x=-8/3

Find the zeros of (3x+6)^2+4(3x+6)+4=0

The zeros of (3x+6)^2+4(3x+6)+4=0 are x=-8/3

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(3 x + 6)^{2} + 4 (3 x + 6) + 4 = 0

x = - \frac{8}{3}

Decimal Notation

x = - 2.66666 \dots

Solution steps

(3 x + 6)^{2} + 4 (3 x + 6) + 4 = 0

Expand

(3 x + 6)^{2} + 4 (3 x + 6) + 4 : 9 x^{2} + 48 x + 64

9 x^{2} + 48 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 9 \cdot 64}{2 \cdot 9}

4 8^{2} - 4 \cdot 9 \cdot 64 = 0

x_{1, 2} = \frac{- 48 \pm 0}{2 \cdot 9}

x = \frac{- 48}{2 \cdot 9}

\frac{- 48}{2 \cdot 9} = - \frac{8}{3}

x = - \frac{8}{3}

The solution to the quadratic equation is:

x = - \frac{8}{3}

r = (- 3)^{2} + (- 2)^{2}

∣ 4 x - 23 ∣ = - 17

\frac{x}{3} = \frac{4}{5}

- 15 x^{4} + 15 x^{2}

(x + 1) (x - \frac{1}{2}) = 0

What are the solutions to the equation (3x+6)^2+4(3x+6)+4=0 ?
The solutions to the equation (3x+6)^2+4(3x+6)+4=0 are x=-8/3
Find the zeros of (3x+6)^2+4(3x+6)+4=0
The zeros of (3x+6)^2+4(3x+6)+4=0 are x=-8/3