What are the solutions to the equation x^2-12x+20=-20 ?

The solutions to the equation x^2-12x+20=-20 are x=6+2i,x=6-2i

Find the zeros of x^2-12x+20=-20

The zeros of x^2-12x+20=-20 are x=6+2i,x=6-2i

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x^{2} - 12 x + 20 = - 20

x = 6 + 2 i, x = 6 - 2 i

Solution steps

x^{2} - 12 x + 20 = - 20

Move

20

to the left side

x^{2} - 12 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 40 : 4 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 i}{2 \cdot 1} : 6 + 2 i

x = \frac{- ( - 12 ) - 4 i}{2 \cdot 1} : 6 - 2 i

The solutions to the quadratic equation are:

x = 6 + 2 i, x = 6 - 2 i

f - 2 x^{5} - 1 x^{4} - 46 x^{3} - 123 x^{2} - 102 x - 26

\frac{4}{5 3}

2 - \frac{5}{6} x = - 8

3 x > 18

\frac{1}{6} - 1

What are the solutions to the equation x^2-12x+20=-20 ?
The solutions to the equation x^2-12x+20=-20 are x=6+2i,x=6-2i
Find the zeros of x^2-12x+20=-20
The zeros of x^2-12x+20=-20 are x=6+2i,x=6-2i