What are the solutions to the equation 5=(x-2)^2 ?

The solutions to the equation 5=(x-2)^2 are x=sqrt(5)+2,x=-sqrt(5)+2

Find the zeros of 5=(x-2)^2

The zeros of 5=(x-2)^2 are x=sqrt(5)+2,x=-sqrt(5)+2

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5 = (x - 2)^{2}

x = 5 + 2, x = - 5 + 2

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

5 = (x - 2)^{2}

Switch sides

(x - 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 5 : x = 5 + 2

Solve

x - 2 = - 5 : x = - 5 + 2

The solutions to the quadratic equation are:

x = 5 + 2, x = - 5 + 2

2 p^{2} - 23 p + 11

39 - 12 w = 7 - 16 w

x^{2} + 15 x + 100 = 0

- x^{2} + 7 x = 1

2 x^{2} + x \geq 6

What are the solutions to the equation 5=(x-2)^2 ?
The solutions to the equation 5=(x-2)^2 are x=sqrt(5)+2,x=-sqrt(5)+2
Find the zeros of 5=(x-2)^2
The zeros of 5=(x-2)^2 are x=sqrt(5)+2,x=-sqrt(5)+2