What is 7x^2+3x>= 5x^2+2 ?

The solution to 7x^2+3x>= 5x^2+2 is x = 1/2

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7x^2+3x>= 5x^2+2

7 x^{2} + 3 x \geq 5 x^{2} + 2

x \leq - 2 or x \geq \frac{1}{2}

Interval Notation

(- \infty, - 2] \cup [\frac{1}{2}, \infty)

Decimal Notation

x \leq - 2 or x \geq 0.5

Solution steps

7 x^{2} + 3 x \geq 5 x^{2} + 2

Rewrite in standard form

2 x^{2} + 3 x - 2 \geq 0

Factor

2 x^{2} + 3 x - 2 : (2 x - 1) (x + 2)

(2 x - 1) (x + 2) \geq 0

Identify the intervals

x \leq - 2 or x \geq \frac{1}{2}

x = \frac{x ^{2}}{2}

x + x + x = - 63

w^{2} + w - 30 = 0

(8^{\frac{1}{2}})^{3}

What is 7x^2+3x>= 5x^2+2 ?
The solution to 7x^2+3x>= 5x^2+2 is x<=-2\lor x>= 1/2