What are the solutions to the equation 4x^2-8x+2=0 ?

The solutions to the equation 4x^2-8x+2=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

Find the zeros of 4x^2-8x+2=0

The zeros of 4x^2-8x+2=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2

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4 x^{2} - 8 x + 2 = 0

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

Decimal Notation

x = 1.70710 \dots, x = 0.29289 \dots

Solution steps

4 x^{2} - 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 \cdot 2 = 42

x_{1, 2} = \frac{- ( - 8 ) \pm 4 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 2}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 2}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 2}{2 \cdot 4} : \frac{2 + 2}{2}

x = \frac{- ( - 8 ) - 4 2}{2 \cdot 4} : \frac{2 - 2}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 2}{2}, x = \frac{2 - 2}{2}

\frac{3}{4} (2)

\frac{4 x - 3}{2} \geq \frac{3 x - 5}{7}

∣ 4 - 5 x ∣ > 2 x - 1

\frac{m + 7}{m ^{2} + 4 m - 21}

x^{2} + 3 x - 378

What are the solutions to the equation 4x^2-8x+2=0 ?
The solutions to the equation 4x^2-8x+2=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2
Find the zeros of 4x^2-8x+2=0
The zeros of 4x^2-8x+2=0 are x=(2+sqrt(2))/2 ,x=(2-sqrt(2))/2