What are the solutions to the equation λ^2-4λ+10=0 ?

The solutions to the equation λ^2-4λ+10=0 are λ=2+sqrt(6)i,λ=2-sqrt(6)i

Find the zeros of λ^2-4λ+10=0

The zeros of λ^2-4λ+10=0 are λ=2+sqrt(6)i,λ=2-sqrt(6)i

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λ^{2} - 4 λ + 10 = 0

λ = 2 + 6 i, λ = 2 - 6 i

Solution steps

λ^{2} - 4 λ + 10 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 10 : 26 i

λ_{1, 2} = \frac{- ( - 4 ) \pm 2 6 i}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 1}, λ_{2} = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 1}

λ = \frac{- ( - 4 ) + 2 6 i}{2 \cdot 1} : 2 + 6 i

λ = \frac{- ( - 4 ) - 2 6 i}{2 \cdot 1} : 2 - 6 i

The solutions to the quadratic equation are:

λ = 2 + 6 i, λ = 2 - 6 i

(x + 3)^{2} + 7 (x + 3) - 18 = 0

2^{\frac{8}{3}}

- 4 = 5 + x

- 2 g + 4 \leq - 6 g - 9

x^{4} - 20 x^{2} + 64 \geq 0

What are the solutions to the equation λ^2-4λ+10=0 ?
The solutions to the equation λ^2-4λ+10=0 are λ=2+sqrt(6)i,λ=2-sqrt(6)i
Find the zeros of λ^2-4λ+10=0
The zeros of λ^2-4λ+10=0 are λ=2+sqrt(6)i,λ=2-sqrt(6)i