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Popular >

simplify \sqrt[5]{-16}*2^{1/5}

Solution

simplify

Solution

- 2

Solution steps

Apply radical rule:

if

n

is odd

Factor integer

16 = 2^{4}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

(2^{4})^{\frac{1}{5}} = 2^{4 \cdot \frac{1}{5}}

= - 2^{4 \cdot \frac{1}{5}} \cdot 2^{\frac{1}{5}}

Refine

= - 2^{\frac{4}{5}} \cdot 2^{\frac{1}{5}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{4}{5}} \cdot 2^{\frac{1}{5}} = 2^{\frac{4}{5} + \frac{1}{5}}

= - 2^{\frac{4}{5} + \frac{1}{5}}

Join

\frac{4}{5} + \frac{1}{5} : 1

= - 2^{1}

Apply rule

a^{1} = a

= - 2

Popular Examples

factor f(2)+g(2)factor

f (2) + g (2)

factor u^6-1 factor

u^{6} - 1

∣ 2 x - 1 ∣ - 5 = - 2

22 = 4 + 6 e

- 4 (- 2 - 6 x) = - 88

Frequently Asked Questions (FAQ)

What is \sqrt[5]{-16}*2^{1/5} ?
The solution to \sqrt[5]{-16}*2^{1/5} is -2