What are the solutions to the equation v^2+8v+6=0 ?

The solutions to the equation v^2+8v+6=0 are v=-4+sqrt(10),v=-4-sqrt(10)

Find the zeros of v^2+8v+6=0

The zeros of v^2+8v+6=0 are v=-4+sqrt(10),v=-4-sqrt(10)

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v^{2} + 8 v + 6 = 0

v = - 4 + 10, v = - 4 - 10

Decimal Notation

v = - 0.83772 \dots, v = - 7.16227 \dots

Solution steps

v^{2} + 8 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 6 = 210

v_{1, 2} = \frac{- 8 \pm 2 10}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 8 + 2 10}{2 \cdot 1}, v_{2} = \frac{- 8 - 2 10}{2 \cdot 1}

v = \frac{- 8 + 2 10}{2 \cdot 1} : - 4 + 10

v = \frac{- 8 - 2 10}{2 \cdot 1} : - 4 - 10

The solutions to the quadratic equation are:

v = - 4 + 10, v = - 4 - 10

x^{2} - 2 x + 8 = 0

4 (3 x + 5) - 3 = 9 x - 7

7 a^{2} - 7 b^{2}

30000 (x) = 2460 (0.06)

- 2 - 18

What are the solutions to the equation v^2+8v+6=0 ?
The solutions to the equation v^2+8v+6=0 are v=-4+sqrt(10),v=-4-sqrt(10)
Find the zeros of v^2+8v+6=0
The zeros of v^2+8v+6=0 are v=-4+sqrt(10),v=-4-sqrt(10)