What are the solutions to the equation 4x^2+1=-4x ?

The solutions to the equation 4x^2+1=-4x are x=-1/2

Find the zeros of 4x^2+1=-4x

The zeros of 4x^2+1=-4x are x=-1/2

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4 x^{2} + 1 = - 4 x

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

4 x^{2} + 1 = - 4 x

Move

4 x

to the left side

4 x^{2} + 1 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

x = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

(36)^{\frac{3}{2}}

\frac{- 9 x ^{- 1} y ^{- 9}}{- 15 x ^{5} y ^{- 3}}

4 x^{3} + 12 x^{2} + 12 x + 4

3^{2} - (\frac{1}{3})^{- 2}

\frac{1}{12 \cdot 1.1} \cdot 2

What are the solutions to the equation 4x^2+1=-4x ?
The solutions to the equation 4x^2+1=-4x are x=-1/2
Find the zeros of 4x^2+1=-4x
The zeros of 4x^2+1=-4x are x=-1/2