What is (a-y)/(w+n)*(w^2-n^2)/(y-a) ?

The solution to (a-y)/(w+n)*(w^2-n^2)/(y-a) is -w+n

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simplify (a-y)/(w+n)*(w^2-n^2)/(y-a)

simplify

\frac{a - y}{w + n} \cdot \frac{w ^{2} - n ^{2}}{y - a}

- w + n

Solution steps

\frac{a - y}{w + n} \cdot \frac{w ^{2} - n ^{2}}{y - a}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( a - y ) ( w ^{2} - n ^{2} )}{( w + n ) ( y - a )}

a - y = - (y - a)

= \frac{- ( y - a ) ( w ^{2} - n ^{2} )}{( w + n ) ( y - a )}

Cancel the common factor:

y - a

= \frac{- ( w ^{2} - n ^{2} )}{w + n}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

w^{2} - n^{2} = (w + n) (w - n)

= \frac{- ( w + n ) ( w - n )}{w + n}

Cancel the common factor:

w + n

= - (w - n)

Apply the distributive law:

- (a - b) = - a + b

- (w - n) = - w + n

= - w + n

\frac{- 2 x + 4}{3 x - 9} \leq \frac{x + 5}{3 x - 9}

x^{2} - 3 x - 18 > 0

- 2 n \leq - 12

\frac{2}{3} (6 x - 5) = 2 - \frac{1}{3} (3 x - 2)

y^{- 1}

What is (a-y)/(w+n)*(w^2-n^2)/(y-a) ?
The solution to (a-y)/(w+n)*(w^2-n^2)/(y-a) is -w+n