What is the answer to (4x+3)/7+(2x+1)/3 =(3x+1)/2 ?

The answer to (4x+3)/7+(2x+1)/3 =(3x+1)/2 is x=1

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(4x+3)/7+(2x+1)/3 =(3x+1)/2

\frac{4 x + 3}{7} + \frac{2 x + 1}{3} = \frac{3 x + 1}{2}

x = 1

Solution steps

\frac{4 x + 3}{7} + \frac{2 x + 1}{3} = \frac{3 x + 1}{2}

Multiply by LCM

6 (4 x + 3) + 14 (2 x + 1) = 21 (3 x + 1)

Expand

6 (4 x + 3) + 14 (2 x + 1) : 52 x + 32

Expand

21 (3 x + 1) : 63 x + 21

52 x + 32 = 63 x + 21

Move

32

to the right side

52 x = 63 x - 11

Move

63 x

to the left side

- 11 x = - 11

Divide both sides by

- 11

x = 1

32 t - 0.8 t^{2} = 0

- 245 - 320 - 26

x (x^{- 1})

\frac{10}{x} > 4

t - 13 \geq 20

What is the answer to (4x+3)/7+(2x+1)/3 =(3x+1)/2 ?
The answer to (4x+3)/7+(2x+1)/3 =(3x+1)/2 is x=1
Solve for x: (4x+3)/7+(2x+1)/3 =(3x+1)/2
The solution is x=1