What are the solutions to the equation 10x^2-75x+132=0 ?

The solutions to the equation 10x^2-75x+132=0 are x=(75+sqrt(345))/(20),x=(75-sqrt(345))/(20)

Find the zeros of 10x^2-75x+132=0

The zeros of 10x^2-75x+132=0 are x=(75+sqrt(345))/(20),x=(75-sqrt(345))/(20)

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10 x^{2} - 75 x + 132 = 0

x = \frac{75 + 345}{20}, x = \frac{75 - 345}{20}

Decimal Notation

x = 4.67870 \dots, x = 2.82129 \dots

Solution steps

10 x^{2} - 75 x + 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 75 ) \pm ( - 75 ) ^{2} - 4 \cdot 10 \cdot 132}{2 \cdot 10}

(- 75)^{2} - 4 \cdot 10 \cdot 132 = 345

x_{1, 2} = \frac{- ( - 75 ) \pm 345}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 75 ) + 345}{2 \cdot 10}, x_{2} = \frac{- ( - 75 ) - 345}{2 \cdot 10}

x = \frac{- ( - 75 ) + 345}{2 \cdot 10} : \frac{75 + 345}{20}

x = \frac{- ( - 75 ) - 345}{2 \cdot 10} : \frac{75 - 345}{20}

The solutions to the quadratic equation are:

x = \frac{75 + 345}{20}, x = \frac{75 - 345}{20}

∣ 2 x - 4 ∣ \geq 8

64 x^{16} y^{4}

- 2 < \frac{x ^{2} - 2}{1 - 2 x} \leq 2

3 x^{2} - 2 x - 21

(\frac{13}{7})^{2}

What are the solutions to the equation 10x^2-75x+132=0 ?
The solutions to the equation 10x^2-75x+132=0 are x=(75+sqrt(345))/(20),x=(75-sqrt(345))/(20)
Find the zeros of 10x^2-75x+132=0
The zeros of 10x^2-75x+132=0 are x=(75+sqrt(345))/(20),x=(75-sqrt(345))/(20)