What are the solutions to the equation (z-2)^2+1=0 ?

The solutions to the equation (z-2)^2+1=0 are z=i+2,z=-i+2

Find the zeros of (z-2)^2+1=0

The zeros of (z-2)^2+1=0 are z=i+2,z=-i+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(z - 2)^{2} + 1 = 0

z = i + 2, z = - i + 2

Solution steps

(z - 2)^{2} + 1 = 0

Move

1

to the right side

(z - 2)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z - 2 = - 1 : z = i + 2

Solve

z - 2 = - - 1 : z = - i + 2

The solutions to the quadratic equation are:

z = i + 2, z = - i + 2

0.99 \cdot S = 7639

\frac{3 z + 5}{- 3} \geq z - 5

3 x - 5 + 4 x = 7 - 2 x - 3

\frac{x}{6} = 25

700 - 35 w = 450 + 15 w

What are the solutions to the equation (z-2)^2+1=0 ?
The solutions to the equation (z-2)^2+1=0 are z=i+2,z=-i+2
Find the zeros of (z-2)^2+1=0
The zeros of (z-2)^2+1=0 are z=i+2,z=-i+2