What are the solutions to the equation x^2-8x+16=16 ?

The solutions to the equation x^2-8x+16=16 are x=8,x=0

Find the zeros of x^2-8x+16=16

The zeros of x^2-8x+16=16 are x=8,x=0

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x^{2} - 8 x + 16 = 16

x = 8, x = 0

Solution steps

x^{2} - 8 x + 16 = 16

Move

16

to the left side

x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

x = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

∣ x - 5 ∣ > 9

\frac{w}{3} \geq 2

(3 - i)^{6}

\frac{h - 50}{5} \geq 1.645

(z^{- 3})^{\frac{1}{9}}

What are the solutions to the equation x^2-8x+16=16 ?
The solutions to the equation x^2-8x+16=16 are x=8,x=0
Find the zeros of x^2-8x+16=16
The zeros of x^2-8x+16=16 are x=8,x=0