What are the solutions to the equation x^2+9x+1=0 ?

The solutions to the equation x^2+9x+1=0 are x=(-9+sqrt(77))/2 ,x=(-9-sqrt(77))/2

Find the zeros of x^2+9x+1=0

The zeros of x^2+9x+1=0 are x=(-9+sqrt(77))/2 ,x=(-9-sqrt(77))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 9 x + 1 = 0

x = \frac{- 9 + 77}{2}, x = \frac{- 9 - 77}{2}

Decimal Notation

x = - 0.11251 \dots, x = - 8.88748 \dots

Solution steps

x^{2} + 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 1 = 77

x_{1, 2} = \frac{- 9 \pm 77}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 77}{2 \cdot 1}, x_{2} = \frac{- 9 - 77}{2 \cdot 1}

x = \frac{- 9 + 77}{2 \cdot 1} : \frac{- 9 + 77}{2}

x = \frac{- 9 - 77}{2 \cdot 1} : \frac{- 9 - 77}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 77}{2}, x = \frac{- 9 - 77}{2}

10 + \frac{54}{- 6}

(3 h^{3})^{4}

- 7 y = - 28

- 6 x + 11 = 7 - 10 x

2 a^{2} + 2 b^{2} - 5 ab

What are the solutions to the equation x^2+9x+1=0 ?
The solutions to the equation x^2+9x+1=0 are x=(-9+sqrt(77))/2 ,x=(-9-sqrt(77))/2
Find the zeros of x^2+9x+1=0
The zeros of x^2+9x+1=0 are x=(-9+sqrt(77))/2 ,x=(-9-sqrt(77))/2