What are the solutions to the equation x^2-15x+52=0 ?

The solutions to the equation x^2-15x+52=0 are x=(15+sqrt(17))/2 ,x=(15-sqrt(17))/2

Find the zeros of x^2-15x+52=0

The zeros of x^2-15x+52=0 are x=(15+sqrt(17))/2 ,x=(15-sqrt(17))/2

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x^{2} - 15 x + 52 = 0

x = \frac{15 + 17}{2}, x = \frac{15 - 17}{2}

Decimal Notation

x = 9.56155 \dots, x = 5.43844 \dots

Solution steps

x^{2} - 15 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 52 = 17

x_{1, 2} = \frac{- ( - 15 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 17}{2 \cdot 1}

x = \frac{- ( - 15 ) + 17}{2 \cdot 1} : \frac{15 + 17}{2}

x = \frac{- ( - 15 ) - 17}{2 \cdot 1} : \frac{15 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 17}{2}, x = \frac{15 - 17}{2}

\frac{2}{14}

∣ 2 + x ∣ \leq 10

5 x^{2} + 4 x y - 12 y^{2}

- 4 + 6 x = 2 (3 x - 2)

\frac{5}{3} - 2

What are the solutions to the equation x^2-15x+52=0 ?
The solutions to the equation x^2-15x+52=0 are x=(15+sqrt(17))/2 ,x=(15-sqrt(17))/2
Find the zeros of x^2-15x+52=0
The zeros of x^2-15x+52=0 are x=(15+sqrt(17))/2 ,x=(15-sqrt(17))/2