What are the solutions to the equation 2(x^2+1)+1=9 ?

The solutions to the equation 2(x^2+1)+1=9 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 2(x^2+1)+1=9

The zeros of 2(x^2+1)+1=9 are x=sqrt(3),x=-sqrt(3)

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2 (x^{2} + 1) + 1 = 9

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

2 (x^{2} + 1) + 1 = 9

Move

1

to the right side

2 (x^{2} + 1) = 8

Divide both sides by

2

x^{2} + 1 = 4

Move

1

to the right side

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

\frac{b ^{10}}{b ^{6}}

\frac{x ^{8}}{x ^{3}}

3 (\frac{2}{3})^{0}

\frac{11}{11}

x^{4} + 18 x^{2} + 81

What are the solutions to the equation 2(x^2+1)+1=9 ?
The solutions to the equation 2(x^2+1)+1=9 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 2(x^2+1)+1=9
The zeros of 2(x^2+1)+1=9 are x=sqrt(3),x=-sqrt(3)