What are the solutions to the equation x^2+6x+4=-2x+4 ?

The solutions to the equation x^2+6x+4=-2x+4 are x=0,x=-8

Find the zeros of x^2+6x+4=-2x+4

The zeros of x^2+6x+4=-2x+4 are x=0,x=-8

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x^{2} + 6 x + 4 = - 2 x + 4

x = 0, x = - 8

Solution steps

x^{2} + 6 x + 4 = - 2 x + 4

Move

4

to the left side

x^{2} + 6 x = - 2 x

Move

2 x

to the left side

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

- 19 < 3 x + 5 \leq 20

5 x^{2} = 55

- 2 x^{3} - 6 x^{2} + 36 x

10!

12 k^{2} + 47 k + 40

What are the solutions to the equation x^2+6x+4=-2x+4 ?
The solutions to the equation x^2+6x+4=-2x+4 are x=0,x=-8
Find the zeros of x^2+6x+4=-2x+4
The zeros of x^2+6x+4=-2x+4 are x=0,x=-8