What are the solutions to the equation x^2+12x-6=0 ?

The solutions to the equation x^2+12x-6=0 are x=-6+sqrt(42),x=-6-sqrt(42)

Find the zeros of x^2+12x-6=0

The zeros of x^2+12x-6=0 are x=-6+sqrt(42),x=-6-sqrt(42)

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x^{2} + 12 x - 6 = 0

x = - 6 + 42, x = - 6 - 42

Decimal Notation

x = 0.48074 \dots, x = - 12.48074 \dots

Solution steps

x^{2} + 12 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 6) = 242

x_{1, 2} = \frac{- 12 \pm 2 42}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 42}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 42}{2 \cdot 1}

x = \frac{- 12 + 2 42}{2 \cdot 1} : - 6 + 42

x = \frac{- 12 - 2 42}{2 \cdot 1} : - 6 - 42

The solutions to the quadratic equation are:

x = - 6 + 42, x = - 6 - 42

3 b^{3} - b^{3} + 2 b

\frac{9 - 8 i}{9 + i}

6 x^{2} = 36

x^{2} = x + 2

10 c + 5 \leq 45

What are the solutions to the equation x^2+12x-6=0 ?
The solutions to the equation x^2+12x-6=0 are x=-6+sqrt(42),x=-6-sqrt(42)
Find the zeros of x^2+12x-6=0
The zeros of x^2+12x-6=0 are x=-6+sqrt(42),x=-6-sqrt(42)