What are the solutions to the equation x^2-12x=-32 ?

The solutions to the equation x^2-12x=-32 are x=8,x=4

Find the zeros of x^2-12x=-32

The zeros of x^2-12x=-32 are x=8,x=4

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x^{2} - 12 x = - 32

x = 8, x = 4

Solution steps

x^{2} - 12 x = - 32

Move

32

to the left side

x^{2} - 12 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 32 = 4

x_{1, 2} = \frac{- ( - 12 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4}{2 \cdot 1} : 8

x = \frac{- ( - 12 ) - 4}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 8, x = 4

2 x^{3} + 8 x^{2} + 10 x + 4

\frac{\frac{5 π}{3}}{2}

\frac{60}{15}

2 8^{\frac{1}{2}}

2 (n + 5) = - 2

What are the solutions to the equation x^2-12x=-32 ?
The solutions to the equation x^2-12x=-32 are x=8,x=4
Find the zeros of x^2-12x=-32
The zeros of x^2-12x=-32 are x=8,x=4