What are the solutions to the equation 2x^2+7x-15=0 ?

The solutions to the equation 2x^2+7x-15=0 are x= 3/2 ,x=-5

Find the zeros of 2x^2+7x-15=0

The zeros of 2x^2+7x-15=0 are x= 3/2 ,x=-5

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2 x^{2} + 7 x - 15 = 0

x = \frac{3}{2}, x = - 5

Decimal Notation

x = 1.5, x = - 5

Solution steps

2 x^{2} + 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 15) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 2}, x_{2} = \frac{- 7 - 13}{2 \cdot 2}

x = \frac{- 7 + 13}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 7 - 13}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 5

(- 4 i) + (- 3 + 4 i)

9 y^{2} - 121 x^{2}

35 \geq 5 (x - 2)

8 x + 1 = 0

\frac{- 6 a ^{- 4} b ^{7}}{- 2 a ^{- 1} b ^{- 7}}

What are the solutions to the equation 2x^2+7x-15=0 ?
The solutions to the equation 2x^2+7x-15=0 are x= 3/2 ,x=-5
Find the zeros of 2x^2+7x-15=0
The zeros of 2x^2+7x-15=0 are x= 3/2 ,x=-5