What are the solutions to the equation 160=490x^2 ?

The solutions to the equation 160=490x^2 are x= 4/7 ,x=-4/7

Find the zeros of 160=490x^2

The zeros of 160=490x^2 are x= 4/7 ,x=-4/7

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160 = 490 x^{2}

x = \frac{4}{7}, x = - \frac{4}{7}

Decimal Notation

x = 0.57142 \dots, x = - 0.57142 \dots

Solution steps

160 = 490 x^{2}

Switch sides

490 x^{2} = 160

Divide both sides by

490

x^{2} = \frac{16}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{49}, x = - \frac{16}{49}

\frac{16}{49} = \frac{4}{7}

- \frac{16}{49} = - \frac{4}{7}

x = \frac{4}{7}, x = - \frac{4}{7}

\frac{2}{5} \cdot 5

x^{2} = 25

x^{2} - 10 x + 16 = 0

2 x - 6 (x - 3) \geq 5

What are the solutions to the equation 160=490x^2 ?
The solutions to the equation 160=490x^2 are x= 4/7 ,x=-4/7
Find the zeros of 160=490x^2
The zeros of 160=490x^2 are x= 4/7 ,x=-4/7