What are the solutions to the equation 9x^2+2x-7=0 ?

The solutions to the equation 9x^2+2x-7=0 are x= 7/9 ,x=-1

Find the zeros of 9x^2+2x-7=0

The zeros of 9x^2+2x-7=0 are x= 7/9 ,x=-1

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9 x^{2} + 2 x - 7 = 0

x = \frac{7}{9}, x = - 1

Decimal Notation

x = 0.77777 \dots, x = - 1

Solution steps

9 x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 ( - 7 )}{2 \cdot 9}

2^{2} - 4 \cdot 9 (- 7) = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 \cdot 9}, x_{2} = \frac{- 2 - 16}{2 \cdot 9}

x = \frac{- 2 + 16}{2 \cdot 9} : \frac{7}{9}

x = \frac{- 2 - 16}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{9}, x = - 1

x^{2} \cdot 3 x^{2}

\frac{1}{16} = 2^{- 4}

- 3 x^{2} + 2 x - 10 = - 3 x

- 3 m = \frac{21}{16}

x^{4} > x

What are the solutions to the equation 9x^2+2x-7=0 ?
The solutions to the equation 9x^2+2x-7=0 are x= 7/9 ,x=-1
Find the zeros of 9x^2+2x-7=0
The zeros of 9x^2+2x-7=0 are x= 7/9 ,x=-1