What are the solutions to the equation -x^2+23x-132=0 ?

The solutions to the equation -x^2+23x-132=0 are x=11,x=12

Find the zeros of -x^2+23x-132=0

The zeros of -x^2+23x-132=0 are x=11,x=12

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- x^{2} + 23 x - 132 = 0

x = 11, x = 12

Solution steps

- x^{2} + 23 x - 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 ( - 1 ) ( - 132 )}{2 ( - 1 )}

2 3^{2} - 4 (- 1) (- 132) = 1

x_{1, 2} = \frac{- 23 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 23 + 1}{2 ( - 1 )}, x_{2} = \frac{- 23 - 1}{2 ( - 1 )}

x = \frac{- 23 + 1}{2 ( - 1 )} : 11

x = \frac{- 23 - 1}{2 ( - 1 )} : 12

The solutions to the quadratic equation are:

x = 11, x = 12

2 π

\frac{7 π}{6} \cdot \frac{180}{π}

\frac{3}{m} + \frac{4}{( m + 1 )}

3 - (- 6)

What are the solutions to the equation -x^2+23x-132=0 ?
The solutions to the equation -x^2+23x-132=0 are x=11,x=12
Find the zeros of -x^2+23x-132=0
The zeros of -x^2+23x-132=0 are x=11,x=12