What are the solutions to the equation x^2-x+0=0 ?

The solutions to the equation x^2-x+0=0 are x=1,x=0

Find the zeros of x^2-x+0=0

The zeros of x^2-x+0=0 are x=1,x=0

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x^{2} - x + 0 = 0

x = 1, x = 0

Solution steps

x^{2} - x + 0 = 0

Refine

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

4 x^{2} - 31 x + 21

8 z - 22 = 3 (3 z + 11) - z

\frac{3 ( x - 2 ) + y ( x - 2 )}{x ^{2} - 4}

- 4 + x < 9

5 x - 1 = 0

What are the solutions to the equation x^2-x+0=0 ?
The solutions to the equation x^2-x+0=0 are x=1,x=0
Find the zeros of x^2-x+0=0
The zeros of x^2-x+0=0 are x=1,x=0