What are the solutions to the equation 2x^2+18x=20 ?

The solutions to the equation 2x^2+18x=20 are x=1,x=-10

Find the zeros of 2x^2+18x=20

The zeros of 2x^2+18x=20 are x=1,x=-10

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2 x^{2} + 18 x = 20

x = 1, x = - 10

Solution steps

2 x^{2} + 18 x = 20

Move

20

to the left side

2 x^{2} + 18 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

1 8^{2} - 4 \cdot 2 (- 20) = 22

x_{1, 2} = \frac{- 18 \pm 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 18 + 22}{2 \cdot 2}, x_{2} = \frac{- 18 - 22}{2 \cdot 2}

x = \frac{- 18 + 22}{2 \cdot 2} : 1

x = \frac{- 18 - 22}{2 \cdot 2} : - 10

The solutions to the quadratic equation are:

x = 1, x = - 10

8 m = 5 m + 12

3 y^{2} = 11 y - 6

(- 3 x)^{- 2}

\frac{9 !}{4 !}

1 - 2 a^{3} + a^{6}

What are the solutions to the equation 2x^2+18x=20 ?
The solutions to the equation 2x^2+18x=20 are x=1,x=-10
Find the zeros of 2x^2+18x=20
The zeros of 2x^2+18x=20 are x=1,x=-10