What are the solutions to the equation s^2+4=0 ?

The solutions to the equation s^2+4=0 are s=2i,s=-2i

Find the zeros of s^2+4=0

The zeros of s^2+4=0 are s=2i,s=-2i

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s^{2} + 4 = 0

s = 2 i, s = - 2 i

Solution steps

s^{2} + 4 = 0

Move

4

to the right side

s^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 4, s = - - 4

- 4 = 2 i

- - 4 = - 2 i

s = 2 i, s = - 2 i

m^{2} - 16 - n^{2} + 36 + 12 m - 8 n

36 x^{2} - 12 x y + y^{2}

(- 2)^{8}

- 3 < 20 - 9 x \leq 6

6 x^{2} - x - 15

What are the solutions to the equation s^2+4=0 ?
The solutions to the equation s^2+4=0 are s=2i,s=-2i
Find the zeros of s^2+4=0
The zeros of s^2+4=0 are s=2i,s=-2i