What are the solutions to the equation 2x^2=x^2+4 ?

The solutions to the equation 2x^2=x^2+4 are x=2,x=-2

Find the zeros of 2x^2=x^2+4

The zeros of 2x^2=x^2+4 are x=2,x=-2

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2 x^{2} = x^{2} + 4

x = 2, x = - 2

Solution steps

2 x^{2} = x^{2} + 4

Move

x^{2}

to the left side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

5 x + 8 - 7 x = - 4 x + 1

2 x^{2} - 2 x - 1 = 0

9 (x - 4) = 18

- 4 (u + 1) = 2 (1 - 2 u) - 6

(x^{2} + 16) (x - 1) (x + 2) \geq 0

What are the solutions to the equation 2x^2=x^2+4 ?
The solutions to the equation 2x^2=x^2+4 are x=2,x=-2
Find the zeros of 2x^2=x^2+4
The zeros of 2x^2=x^2+4 are x=2,x=-2