What are the solutions to the equation w^2+14w-15=0 ?

The solutions to the equation w^2+14w-15=0 are w=1,w=-15

Find the zeros of w^2+14w-15=0

The zeros of w^2+14w-15=0 are w=1,w=-15

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w^{2} + 14 w - 15 = 0

w = 1, w = - 15

Solution steps

w^{2} + 14 w - 15 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 15) = 16

w_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 14 + 16}{2 \cdot 1}, w_{2} = \frac{- 14 - 16}{2 \cdot 1}

w = \frac{- 14 + 16}{2 \cdot 1} : 1

w = \frac{- 14 - 16}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

w = 1, w = - 15

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What are the solutions to the equation w^2+14w-15=0 ?
The solutions to the equation w^2+14w-15=0 are w=1,w=-15
Find the zeros of w^2+14w-15=0
The zeros of w^2+14w-15=0 are w=1,w=-15