What is factor 2n^2+3n-9 ?

The solution to factor 2n^2+3n-9 is (2n-3)(n+3)

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factor 2n^2+3n-9

factor

2 n^{2} + 3 n - 9

(2 n - 3) (n + 3)

Solution steps

2 n^{2} + 3 n - 9

Break the expression into groups

= (2 n^{2} - 3 n) + (6 n - 9)

Factor out

n

from

2 n^{2} - 3 n : n (2 n - 3)

Factor out

3

from

6 n - 9 : 3 (2 n - 3)

= n (2 n - 3) + 3 (2 n - 3)

Factor out common term

2 n - 3

= (2 n - 3) (n + 3)

49 x^{2} - 42 x y + 9 y^{2}

\frac{8}{3} = 8 x - 4 x^{2}

50 x + 6 > - 94

y^{2} + 8 y + 16 = 0

3 \leq ∣ 3 y - 6 ∣ \leq 9