What are the solutions to the equation 5x^2=-4 ?

The solutions to the equation 5x^2=-4 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

Find the zeros of 5x^2=-4

The zeros of 5x^2=-4 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i

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5 x^{2} = - 4

x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

5 x^{2} = - 4

Divide both sides by

5

x^{2} = - \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{5}, x = - - \frac{4}{5}

- \frac{4}{5} = \frac{2}{5} i

- - \frac{4}{5} = - \frac{2}{5} i

x = \frac{2}{5} i, x = - \frac{2}{5} i

2 + \frac{3}{4} x = \frac{9}{10}

5 x = 20

144 = 2 (y + 6) + 2 y

\frac{47 - 13 i}{40 + 9 i}

- 3 + 5108

What are the solutions to the equation 5x^2=-4 ?
The solutions to the equation 5x^2=-4 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i
Find the zeros of 5x^2=-4
The zeros of 5x^2=-4 are x= 2/(sqrt(5))i,x=-2/(sqrt(5))i