What are the solutions to the equation -4x^2-8x-3=-3-5x^2 ?

The solutions to the equation -4x^2-8x-3=-3-5x^2 are x=8,x=0

Find the zeros of -4x^2-8x-3=-3-5x^2

The zeros of -4x^2-8x-3=-3-5x^2 are x=8,x=0

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- 4 x^{2} - 8 x - 3 = - 3 - 5 x^{2}

x = 8, x = 0

Solution steps

- 4 x^{2} - 8 x - 3 = - 3 - 5 x^{2}

Move

5 x^{2}

to the left side

x^{2} - 8 x - 3 = - 3

Move

3

to the left side

x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

x = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

\frac{4 k}{k - 6} + \frac{k}{6 - k}

2 \times 1 + 2 \times \frac{24}{4}

∣ 4 x + 2 ∣ < 26

\frac{4}{3} \cdot \frac{1}{4}

3 m^{4} - 48 n^{2}

What are the solutions to the equation -4x^2-8x-3=-3-5x^2 ?
The solutions to the equation -4x^2-8x-3=-3-5x^2 are x=8,x=0
Find the zeros of -4x^2-8x-3=-3-5x^2
The zeros of -4x^2-8x-3=-3-5x^2 are x=8,x=0