What are the solutions to the equation 6x^2-8=x ?

The solutions to the equation 6x^2-8=x are x=(1+sqrt(193))/(12),x=(1-sqrt(193))/(12)

Find the zeros of 6x^2-8=x

The zeros of 6x^2-8=x are x=(1+sqrt(193))/(12),x=(1-sqrt(193))/(12)

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6 x^{2} - 8 = x

x = \frac{1 + 193}{12}, x = \frac{1 - 193}{12}

Decimal Notation

x = 1.24103 \dots, x = - 1.07437 \dots

Solution steps

6 x^{2} - 8 = x

Move

x

to the left side

6 x^{2} - 8 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 8 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 8) = 193

x_{1, 2} = \frac{- ( - 1 ) \pm 193}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 193}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 193}{2 \cdot 6}

x = \frac{- ( - 1 ) + 193}{2 \cdot 6} : \frac{1 + 193}{12}

x = \frac{- ( - 1 ) - 193}{2 \cdot 6} : \frac{1 - 193}{12}

The solutions to the quadratic equation are:

x = \frac{1 + 193}{12}, x = \frac{1 - 193}{12}

5 x - 8 \geq - 8 x + 18

x^{2} < 3 x

12 y^{2} + 21 y^{5}

x^{2} - 3 x + 27 = 6 x + 7

x^{2} + 7 x + 10 > 0

What are the solutions to the equation 6x^2-8=x ?
The solutions to the equation 6x^2-8=x are x=(1+sqrt(193))/(12),x=(1-sqrt(193))/(12)
Find the zeros of 6x^2-8=x
The zeros of 6x^2-8=x are x=(1+sqrt(193))/(12),x=(1-sqrt(193))/(12)