What are the solutions to the equation 3x^2-2=19 ?

The solutions to the equation 3x^2-2=19 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 3x^2-2=19

The zeros of 3x^2-2=19 are x=sqrt(7),x=-sqrt(7)

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3 x^{2} - 2 = 19

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

3 x^{2} - 2 = 19

Move

2

to the right side

3 x^{2} = 21

Divide both sides by

3

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

\frac{∣ x + 1 ∣}{∣ 1 - 2 x ∣} \geq 1

x^{\frac{3}{2}} - 8 x^{\frac{1}{2}}

3 x^{2} - 24 x + 50 = 0

\frac{12 x ^{8} y ^{6}}{18 x ^{4} y ^{3}}

- 3 (u + 5) + 2 = 4 (u + 2)

What are the solutions to the equation 3x^2-2=19 ?
The solutions to the equation 3x^2-2=19 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 3x^2-2=19
The zeros of 3x^2-2=19 are x=sqrt(7),x=-sqrt(7)