What are the solutions to the equation 2x^2-x-3=0 ?

The solutions to the equation 2x^2-x-3=0 are x= 3/2 ,x=-1

Find the zeros of 2x^2-x-3=0

The zeros of 2x^2-x-3=0 are x= 3/2 ,x=-1

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2 x^{2} - x - 3 = 0

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

\frac{4}{5} - 2

\frac{2 ( x + h ) - 2 x}{h}

\frac{7 x - 6}{2} = 5 x + 5

\frac{6 - i}{2 - 3 i}

∣ x - 3 ∣ \leq 3

What are the solutions to the equation 2x^2-x-3=0 ?
The solutions to the equation 2x^2-x-3=0 are x= 3/2 ,x=-1
Find the zeros of 2x^2-x-3=0
The zeros of 2x^2-x-3=0 are x= 3/2 ,x=-1