What is factor n^2-18n+56 ?

The solution to factor n^2-18n+56 is (n-4)(n-14)

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factor n^2-18n+56

factor

n^{2} - 18 n + 56

(n - 4) (n - 14)

Solution steps

n^{2} - 18 n + 56

Break the expression into groups

= (n^{2} - 4 n) + (- 14 n + 56)

Factor out

n

from

n^{2} - 4 n : n (n - 4)

Factor out

- 14

from

- 14 n + 56 : - 14 (n - 4)

= n (n - 4) - 14 (n - 4)

Factor out common term

n - 4

= (n - 4) (n - 14)

3 a^{4} + 16 a^{2} + 20

x^{2} + \frac{19 x}{2} + \frac{9}{2} = 0

\frac{( x - 4 ) ( x + 5 )}{x - 6} \leq 0

- 3 + 4 x > 13

\frac{1}{5} + \frac{3}{10}