What are the solutions to the equation (x+4)(20-x)=63 ?

The solutions to the equation (x+4)(20-x)=63 are x=-1,x=17

Find the zeros of (x+4)(20-x)=63

The zeros of (x+4)(20-x)=63 are x=-1,x=17

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(x + 4) (20 - x) = 63

x = - 1, x = 17

Solution steps

(x + 4) (20 - x) = 63

Expand

(x + 4) (20 - x) : 16 x - x^{2} + 80

16 x - x^{2} + 80 = 63

Move

63

to the left side

- x^{2} + 16 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) \cdot 17}{2 ( - 1 )}

1 6^{2} - 4 (- 1) \cdot 17 = 18

x_{1, 2} = \frac{- 16 \pm 18}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 18}{2 ( - 1 )}, x_{2} = \frac{- 16 - 18}{2 ( - 1 )}

x = \frac{- 16 + 18}{2 ( - 1 )} : - 1

x = \frac{- 16 - 18}{2 ( - 1 )} : 17

The solutions to the quadratic equation are:

x = - 1, x = 17

e^{0.4}

3 x^{4} + 3 x^{3} - 12 x^{2} - 12 x

v^{2} - v - 30 = 0

x^{4} - 8 x^{3} + 18 x^{2} - 27

- 7 t - 5 - 7 t = - 3 - 14 t - 11

What are the solutions to the equation (x+4)(20-x)=63 ?
The solutions to the equation (x+4)(20-x)=63 are x=-1,x=17
Find the zeros of (x+4)(20-x)=63
The zeros of (x+4)(20-x)=63 are x=-1,x=17