What are the solutions to the equation x^2-x+1=43 ?

The solutions to the equation x^2-x+1=43 are x=7,x=-6

Find the zeros of x^2-x+1=43

The zeros of x^2-x+1=43 are x=7,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x + 1 = 43

x = 7, x = - 6

Solution steps

x^{2} - x + 1 = 43

Move

43

to the left side

x^{2} - x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 42) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 1}

x = \frac{- ( - 1 ) + 13}{2 \cdot 1} : 7

x = \frac{- ( - 1 ) - 13}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 7, x = - 6

5 + 25

- 4 x^{2} - 28 x - 48

x^{2} - 5 x - 36

361

\frac{2 x}{3} + \frac{3 x + 5}{2} \leq 5

What are the solutions to the equation x^2-x+1=43 ?
The solutions to the equation x^2-x+1=43 are x=7,x=-6
Find the zeros of x^2-x+1=43
The zeros of x^2-x+1=43 are x=7,x=-6