What are the solutions to the equation x^2=16x+10 ?

The solutions to the equation x^2=16x+10 are x=8+sqrt(74),x=8-sqrt(74)

Find the zeros of x^2=16x+10

The zeros of x^2=16x+10 are x=8+sqrt(74),x=8-sqrt(74)

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x^{2} = 16 x + 10

x = 8 + 74, x = 8 - 74

Decimal Notation

x = 16.60232 \dots, x = - 0.60232 \dots

Solution steps

x^{2} = 16 x + 10

Move

10

to the left side

x^{2} - 10 = 16 x

Move

16 x

to the left side

x^{2} - 10 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 16 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 10) = 274

x_{1, 2} = \frac{- ( - 16 ) \pm 2 74}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 74}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 2 74}{2 \cdot 1}

x = \frac{- ( - 16 ) + 2 74}{2 \cdot 1} : 8 + 74

x = \frac{- ( - 16 ) - 2 74}{2 \cdot 1} : 8 - 74

The solutions to the quadratic equation are:

x = 8 + 74, x = 8 - 74

0.21 t - 0.6 + 0.16 t \leq 1.25

(x - 5)^{2} = 49

[3 m - 2] \geq 1

9 m^{6} - 36 n^{8}

(3 - 2 i)^{2}

What are the solutions to the equation x^2=16x+10 ?
The solutions to the equation x^2=16x+10 are x=8+sqrt(74),x=8-sqrt(74)
Find the zeros of x^2=16x+10
The zeros of x^2=16x+10 are x=8+sqrt(74),x=8-sqrt(74)