What are the solutions to the equation (z+7)^2=-81 ?

The solutions to the equation (z+7)^2=-81 are z=9i-7,z=-9i-7

Find the zeros of (z+7)^2=-81

The zeros of (z+7)^2=-81 are z=9i-7,z=-9i-7

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(z + 7)^{2} = - 81

z = 9 i - 7, z = - 9 i - 7

Solution steps

(z + 7)^{2} = - 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 7 = - 81 : z = 9 i - 7

Solve

z + 7 = - - 81 : z = - 9 i - 7

The solutions to the quadratic equation are:

z = 9 i - 7, z = - 9 i - 7

\frac{4 ( 0.999 )}{( 0.999 ) - 1}

2 x - 3 > 5 or x - 3 < - 1

\frac{2 - 3}{- 2 - 5}

0.4 \cdot 0.9 = x \cdot 1.1

x^{4} + x^{2} - 12

What are the solutions to the equation (z+7)^2=-81 ?
The solutions to the equation (z+7)^2=-81 are z=9i-7,z=-9i-7
Find the zeros of (z+7)^2=-81
The zeros of (z+7)^2=-81 are z=9i-7,z=-9i-7