What is factor b^2+9b+20 ?

The solution to factor b^2+9b+20 is (b+4)(b+5)

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factor b^2+9b+20

factor

b^{2} + 9 b + 20

(b + 4) (b + 5)

Solution steps

b^{2} + 9 b + 20

Break the expression into groups

= (b^{2} + 4 b) + (5 b + 20)

Factor out

b

from

b^{2} + 4 b : b (b + 4)

Factor out

5

from

5 b + 20 : 5 (b + 4)

= b (b + 4) + 5 (b + 4)

Factor out common term

b + 4

= (b + 4) (b + 5)

(- \frac{2}{5})^{5}

\frac{1}{5 + 6}

(5 x^{2} y^{3})^{2}

9 (2 k + 3) + 2 = 11 (k - 5)

\frac{3}{4 - 9 i}