What is factor n^2-3n-40 ?

The solution to factor n^2-3n-40 is (n+5)(n-8)

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factor n^2-3n-40

factor

n^{2} - 3 n - 40

(n + 5) (n - 8)

Solution steps

n^{2} - 3 n - 40

Break the expression into groups

= (n^{2} + 5 n) + (- 8 n - 40)

Factor out

n

from

n^{2} + 5 n : n (n + 5)

Factor out

- 8

from

- 8 n - 40 : - 8 (n + 5)

= n (n + 5) - 8 (n + 5)

Factor out common term

n + 5

= (n + 5) (n - 8)

\frac{5}{2} + 1

\frac{5}{x - 3} > \frac{3}{x + 1}

\frac{2}{3} + \frac{2}{7}

6 x^{4} - 10 x^{3} - 6 x^{2}

\frac{1}{125}