What is [(8abc)/(2a^2b^2c^3)]^{-2} ?

The solution to [(8abc)/(2a^2b^2c^3)]^{-2} is (a^2b^2c^4)/(16)

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simplify [(8abc)/(2a^2b^2c^3)]^{-2}

simplify

[\frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}}]^{- 2}

\frac{a ^{2} b ^{2} c ^{4}}{16}

Solution steps

(\frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}})^{- 2} = \frac{1}{( \frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}} ) ^{2}}

= \frac{1}{( \frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}} ) ^{2}}

Simplify

(\frac{8 ab c}{2 a ^{2} b ^{2} c ^{3}})^{2} : \frac{16}{a ^{2} b ^{2} c ^{4}}

= \frac{1}{\frac{16}{a ^{2} b ^{2} c ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{2} b ^{2} c ^{4}}{16}

3 x^{2} - 11 x > 20

298

x + 9 = 3 x - 3

5 f = - 75

6 (r - 4) = 24

What is [(8abc)/(2a^2b^2c^3)]^{-2} ?
The solution to [(8abc)/(2a^2b^2c^3)]^{-2} is (a^2b^2c^4)/(16)