What are the solutions to the equation -7x^2-5x+5=0 ?

The solutions to the equation -7x^2-5x+5=0 are x=-(5+sqrt(165))/(14),x=(sqrt(165)-5)/(14)

Find the zeros of -7x^2-5x+5=0

The zeros of -7x^2-5x+5=0 are x=-(5+sqrt(165))/(14),x=(sqrt(165)-5)/(14)

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- 7 x^{2} - 5 x + 5 = 0

x = - \frac{5 + 165}{14}, x = \frac{165 - 5}{14}

Decimal Notation

x = - 1.27465 \dots, x = 0.56037 \dots

Solution steps

- 7 x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 7 ) \cdot 5}{2 ( - 7 )}

(- 5)^{2} - 4 (- 7) \cdot 5 = 165

x_{1, 2} = \frac{- ( - 5 ) \pm 165}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 165}{2 ( - 7 )}, x_{2} = \frac{- ( - 5 ) - 165}{2 ( - 7 )}

x = \frac{- ( - 5 ) + 165}{2 ( - 7 )} : - \frac{5 + 165}{14}

x = \frac{- ( - 5 ) - 165}{2 ( - 7 )} : \frac{165 - 5}{14}

The solutions to the quadratic equation are:

x = - \frac{5 + 165}{14}, x = \frac{165 - 5}{14}

x^{2} + 7 x - 18 = 0

∣ 3 x - 2 ∣ = 4

- 8 y \geq 56

\frac{6}{6}

4 (7 - w) + 4 w < 25

What are the solutions to the equation -7x^2-5x+5=0 ?
The solutions to the equation -7x^2-5x+5=0 are x=-(5+sqrt(165))/(14),x=(sqrt(165)-5)/(14)
Find the zeros of -7x^2-5x+5=0
The zeros of -7x^2-5x+5=0 are x=-(5+sqrt(165))/(14),x=(sqrt(165)-5)/(14)