What are the solutions to the equation x^2-x=log_{5}(25) ?

The solutions to the equation x^2-x=log_{5}(25) are x=2,x=-1

Find the zeros of x^2-x=log_{5}(25)

The zeros of x^2-x=log_{5}(25) are x=2,x=-1

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x^{2} - x = lo g_{5} (25)

x = 2, x = - 1

Solution steps

x^{2} - x = lo g_{5} (25)

Expand

lo g_{5} (25) : 2

x^{2} - x = 2

Move

2

to the left side

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

- x^{2} - 7 x - 4 = 0

x + 3 \geq 2

\frac{3}{4} x - 2 = \frac{5}{12}

a^{7} - a b^{6}

∣ 1 - 4 x ∣ - 1 = 5

What are the solutions to the equation x^2-x=log_{5}(25) ?
The solutions to the equation x^2-x=log_{5}(25) are x=2,x=-1
Find the zeros of x^2-x=log_{5}(25)
The zeros of x^2-x=log_{5}(25) are x=2,x=-1