What are the solutions to the equation 4x^2+20x+24=0 ?

The solutions to the equation 4x^2+20x+24=0 are x=-2,x=-3

Find the zeros of 4x^2+20x+24=0

The zeros of 4x^2+20x+24=0 are x=-2,x=-3

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4 x^{2} + 20 x + 24 = 0

x = - 2, x = - 3

Solution steps

4 x^{2} + 20 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 24 = 4

x_{1, 2} = \frac{- 20 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 4}{2 \cdot 4}, x_{2} = \frac{- 20 - 4}{2 \cdot 4}

x = \frac{- 20 + 4}{2 \cdot 4} : - 2

x = \frac{- 20 - 4}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

x - \frac{7 x + 11}{24} = \frac{2 x - 1}{3}

3 w^{2} + 10 w + 8

4 x^{2} - 9 = 0

6 x^{3} + 9 x^{2} + 3 x

4 x > 28

What are the solutions to the equation 4x^2+20x+24=0 ?
The solutions to the equation 4x^2+20x+24=0 are x=-2,x=-3
Find the zeros of 4x^2+20x+24=0
The zeros of 4x^2+20x+24=0 are x=-2,x=-3