What are the solutions to the equation 3x^2+3x+1=0 ?

The solutions to the equation 3x^2+3x+1=0 are x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6

Find the zeros of 3x^2+3x+1=0

The zeros of 3x^2+3x+1=0 are x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6

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3 x^{2} + 3 x + 1 = 0

x = - \frac{1}{2} + i \frac{3}{6}, x = - \frac{1}{2} - i \frac{3}{6}

Solution steps

3 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

Simplify

3^{2} - 4 \cdot 3 \cdot 1 : 3 i

x_{1, 2} = \frac{- 3 \pm 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 3 i}{2 \cdot 3}, x_{2} = \frac{- 3 - 3 i}{2 \cdot 3}

x = \frac{- 3 + 3 i}{2 \cdot 3} : - \frac{1}{2} + i \frac{3}{6}

x = \frac{- 3 - 3 i}{2 \cdot 3} : - \frac{1}{2} - i \frac{3}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3}{6}, x = - \frac{1}{2} - i \frac{3}{6}

\frac{3}{7} + \frac{1}{2}

(- 729)^{\frac{4}{3}}

r^{2} + 2 r

\frac{9}{2} \cdot 2

\frac{x ^{- 2}}{y ^{- 6}}

What are the solutions to the equation 3x^2+3x+1=0 ?
The solutions to the equation 3x^2+3x+1=0 are x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6
Find the zeros of 3x^2+3x+1=0
The zeros of 3x^2+3x+1=0 are x=-1/2+i(sqrt(3))/6 ,x=-1/2-i(sqrt(3))/6